Interactions of High Energy Particles with NucleiNational Bureau of Standards, 1975 - 69 pages |
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Page 3
... limit E → we have to have V ~ EV ' where V ' is energy independent . Otherwise the high energy solution of the Schrödinger equation reduces to the Born approximation . 2m 3 A ¥ + k2 = = ᏙᎲ , h2 = eikap ( x , y , z ) , 22 a2 Ay = eikz ...
... limit E → we have to have V ~ EV ' where V ' is energy independent . Otherwise the high energy solution of the Schrödinger equation reduces to the Born approximation . 2m 3 A ¥ + k2 = = ᏙᎲ , h2 = eikap ( x , y , z ) , 22 a2 Ay = eikz ...
Page 5
... limit E → we have to have ( 1 - α3 ) -0 , ( 1 + α3 ) 24 . . ( 2.2 ) ( 2.3 ) This is because the right - hand side of ( 2.3 ) does not contain the energy , E. We multiply eq ( 2.3 ) from the left by 12 ( 1 + as ) and get ( note that ( 1 ...
... limit E → we have to have ( 1 - α3 ) -0 , ( 1 + α3 ) 24 . . ( 2.2 ) ( 2.3 ) This is because the right - hand side of ( 2.3 ) does not contain the energy , E. We multiply eq ( 2.3 ) from the left by 12 ( 1 + as ) and get ( note that ( 1 ...
Page 9
... high energy limit whereas in the second case they do not . K One may ask oneself a question : is there any simple way of telling which values of x and x result in decoupling of various spin states in the high energy limit ? The answer ...
... high energy limit whereas in the second case they do not . K One may ask oneself a question : is there any simple way of telling which values of x and x result in decoupling of various spin states in the high energy limit ? The answer ...
Page 10
... high energy limit and for the gyromagnetic ratio g = 2 ( hence when ( 2.7 ) is valid because the definition of g is through the equation M = g ( e / 2m ) S ) the projection of the polarization on the direction of motion is constant ...
... high energy limit and for the gyromagnetic ratio g = 2 ( hence when ( 2.7 ) is valid because the definition of g is through the equation M = g ( e / 2m ) S ) the projection of the polarization on the direction of motion is constant ...
Page 14
... high energy limit . For example , the limit when A and B become very large was considered [ 13 ] ( compare also [ 12 ] ) : lim M = A , B → ∞ ik 2π d2b exp ( i △ · b ) [ 1– e xp ( − AB [ - d2s « « > d2s « b ) p ( a ) ( s ( a ) ) y ...
... high energy limit . For example , the limit when A and B become very large was considered [ 13 ] ( compare also [ 12 ] ) : lim M = A , B → ∞ ik 2π d2b exp ( i △ · b ) [ 1– e xp ( − AB [ - d2s « « > d2s « b ) p ( a ) ( s ( a ) ) y ...
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absorption additivity analysis approximately assume attenuation beam coherent collision complete components compute consider contribution corrections Coulomb Coulomb interactions coupling cross section db exp db exp i▲·b depend describe deuteron diffractive production processes discussed effects elastic scattering elastic scattering amplitude equation example excited existence experimental experiments expression fact factor field final formula forward given gives Glauber ground hadrons Hence high energy limit important incident particle inelastic initial Institute interactions introduce magnetic mass measurement momentum transfer multiple scattering Note nuclear nuclear targets nuclei nucleon numbers objects obtained parameters phase shifts photon photoproduction physical position possible problem profiles regeneration shadowing single Standards step strong structure technical vector meson wave function weak