## Interactions of High Energy Particles with Nuclei |

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and assuming that the particle goes through the target so fast that all the nucleons are ' frozen ' at certain positions , we get for the amplitude Mfi = ik 27 / d3rı dr ... ray , * ( r ... ra ) | bexp (

and assuming that the particle goes through the target so fast that all the nucleons are ' frozen ' at certain positions , we get for the amplitude Mfi = ik 27 / d3rı dr ... ray , * ( r ... ra ) | bexp (

**iA**+**b**) × { 1 -**exp**[ Σx ; (**b**... Page 4

The amplitude for the particle to scatter from k to k ' is : M ( k ' , k ) = - ≈ m 2π m 2π d3r exp ( -ik ' • r ) V ( r ) ( r ) 81 dzeik V ( b , z ) exp exp ( − : S_dzV ( b , 2 ' ) ) d2b

The amplitude for the particle to scatter from k to k ' is : M ( k ' , k ) = - ≈ m 2π m 2π d3r exp ( -ik ' • r ) V ( r ) ( r ) 81 dzeik V ( b , z ) exp exp ( − : S_dzV ( b , 2 ' ) ) d2b

**exp**(**iA.b**) [ ** ik = 1 db**exp**(**ia - b**) [ 1- ... Page 5

**E**( 1 - α3 ) = [ -**i a**• ▽ + ßm - Kẞ ( Σ ·**B**-**ia E**) + eV ] ø . Hence , in the limit**E**→ we have to have ( 1 - α3 ) -0 , ( 1 + α3 ) 24 . . ( 2.2 ) ( 2.3 ) This is because the right - hand side of ( 2.3 ) does not contain the energy ... Page 6

... k ) == m ↓ = u ( k )

... k ) == m ↓ = u ( k )

**exp**( ikz - ie [ ' _ dz'V ( b , 2 ' ) ) , 22 [ d3rī svoеV ( b , 2 ) , where = u ( k ' )**exp**( iEz +**iA**.**b**) , we get m f · .00 z ) 91x ( k ' , k ) = " " , û ( k ' ) rou ( k ) i ƒ db**exp**( i △ -b ) [ 1 -**exp**... Page 8

Take , e.g. , pure Coulomb scattering ( B = 0 , V = Coulomb potential ) in eq ( 2.5 ) : ax -i- dz = ax . ... potential is present ( hence B = 0 , but E0 ) , we have M ( A ) ~ ix , + + { S db

Take , e.g. , pure Coulomb scattering ( B = 0 , V = Coulomb potential ) in eq ( 2.5 ) : ax -i- dz = ax . ... potential is present ( hence B = 0 , but E0 ) , we have M ( A ) ~ ix , + + { S db

**exp**(**ia - b**) [ 1– exp ( -ie [ ** dz V ( b ...### What people are saying - Write a review

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