Interactions of High Energy Particles with Nuclei |
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Page 18
From our discussion of the components of σTOT ( σel , σDT , σPROD ) it follows that the measure- ments of σror may be a good way of finding out whether the inelastic shadowing ( or inelastic screening ) corrections are important at very ...
From our discussion of the components of σTOT ( σel , σDT , σPROD ) it follows that the measure- ments of σror may be a good way of finding out whether the inelastic shadowing ( or inelastic screening ) corrections are important at very ...
Page 19
Let us consider first the Coulomb corrections for heavy nuclei . One can , in principle , use the individual amplitudes which have Coulomb interactions built into them ( this very tedious cal- culation has been done , e.g. , in refs .
Let us consider first the Coulomb corrections for heavy nuclei . One can , in principle , use the individual amplitudes which have Coulomb interactions built into them ( this very tedious cal- culation has been done , e.g. , in refs .
Page 22
These two factors make Coulomb corrections insignificant in do DT / do . How important are the details of the target nucleus wave function ? Not very important . The most important are general characteristics : density distributions ...
These two factors make Coulomb corrections insignificant in do DT / do . How important are the details of the target nucleus wave function ? Not very important . The most important are general characteristics : density distributions ...
Page 23
SA ' ) ( 3.8 ) Then we can compute the correction factor to M = ( M ( △ ; 81 ... SA ) ) assuming the wave function to be in the form of a product of the c.m. wave function and the internal wave function .
SA ' ) ( 3.8 ) Then we can compute the correction factor to M = ( M ( △ ; 81 ... SA ) ) assuming the wave function to be in the form of a product of the c.m. wave function and the internal wave function .
Page 24
Hence if we can factor out the c.m. wave function from the product = II ; ; ( r ; ) we can stick to calculating M with Yo but we have to multiply it by a correction factor : ( R ( r ) | exp ( i △ · r ) | R ( r ) ) −1 .
Hence if we can factor out the c.m. wave function from the product = II ; ; ( r ; ) we can stick to calculating M with Yo but we have to multiply it by a correction factor : ( R ( r ) | exp ( i △ · r ) | R ( r ) ) −1 .
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