Interactions of High Energy Particles with Nuclei |
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Page 8
If it does not , there is no context in which one could talk about additivity of phase shifts . In general the additivity does not occur . Take , e.g. , pure Coulomb scattering ( B = 0 , V = Coulomb potential ) in eq ( 2.5 ) : ax ...
If it does not , there is no context in which one could talk about additivity of phase shifts . In general the additivity does not occur . Take , e.g. , pure Coulomb scattering ( B = 0 , V = Coulomb potential ) in eq ( 2.5 ) : ax ...
Page 9
... для -ie ax , aA , F MY a AH axy дах , We shall choose Av = i & us V ( r ) ( just the static Coulomb field ) . The results of a long and involved analysis ( 9 , 10 ] are as follows : 1. We recover the principle of additivity of phase ...
... для -ie ax , aA , F MY a AH axy дах , We shall choose Av = i & us V ( r ) ( just the static Coulomb field ) . The results of a long and involved analysis ( 9 , 10 ] are as follows : 1. We recover the principle of additivity of phase ...
Page 18
The remaining important corrections to be discussed ( although they are , in principle , included in the algorithm presented above ) are : ( i ) the Coulomb corrections which play an important role in elastic scattering from nuclei of ...
The remaining important corrections to be discussed ( although they are , in principle , included in the algorithm presented above ) are : ( i ) the Coulomb corrections which play an important role in elastic scattering from nuclei of ...
Page 19
Let us consider first the Coulomb corrections for heavy nuclei . One can , in principle , use the individual amplitudes which have Coulomb interactions built into them ( this very tedious calculation has been done , e.g. , in refs .
Let us consider first the Coulomb corrections for heavy nuclei . One can , in principle , use the individual amplitudes which have Coulomb interactions built into them ( this very tedious calculation has been done , e.g. , in refs .
Page 20
( 120 ) n exp [ -in In ( 42 / 4k2 ) ] e2100 Ao / 2k where n = Ze / v , = 0o = arg 1 ( 1 + in ) . and hence we get the convergent expression for the complete amplitude by adding and subtracting a Coulomb point charge amplitude : M = ik ...
( 120 ) n exp [ -in In ( 42 / 4k2 ) ] e2100 Ao / 2k where n = Ze / v , = 0o = arg 1 ( 1 + in ) . and hence we get the convergent expression for the complete amplitude by adding and subtracting a Coulomb point charge amplitude : M = ik ...
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