International Library of Technology: A Series of Textbooks for Persons Engaged in the Engineering Professions and Trades, Or for Those who Desire Information Concerning Them, Volume 96International Textbook Company, 1908 |
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Results 1-5 of 64
Page 14
... zero . 2. The last string PE , Fig . 6 , of the funicular must coin- cide with the first PA ; for , otherwise , the forces would be equivalent to a couple , as explained in the last article . Conversely , if the force polygon of a ...
... zero . 2. The last string PE , Fig . 6 , of the funicular must coin- cide with the first PA ; for , otherwise , the forces would be equivalent to a couple , as explained in the last article . Conversely , if the force polygon of a ...
Page 18
... zero , whence , as before , R - 4W + R , = 0 ; R. = 4W - R1 = 4W - 2W = 2W 2 In this case , where the load is symmetrical , it is evidently unnecessary to write out these equations , since the reactions • must be equal , and each must ...
... zero , whence , as before , R - 4W + R , = 0 ; R. = 4W - R1 = 4W - 2W = 2W 2 In this case , where the load is symmetrical , it is evidently unnecessary to write out these equations , since the reactions • must be equal , and each must ...
Page 29
... zero shear at i , and negative shears beyond . These negative shears , which are smaller than the dead - load shears , are equal to the difference between the dead - load negative and the live - load positive shears . They are in fact ...
... zero shear at i , and negative shears beyond . These negative shears , which are smaller than the dead - load shears , are equal to the difference between the dead - load negative and the live - load positive shears . They are in fact ...
Page 35
... zero at the end - a result not altogether undesirable , as it tends to increase the size of the small web members near the center . دا GENERAL METHODS OF CALCULATING STRESSES INTRODUCTION 64. Conditions of § 67 35 STRESSES IN BRIDGE ...
... zero at the end - a result not altogether undesirable , as it tends to increase the size of the small web members near the center . دا GENERAL METHODS OF CALCULATING STRESSES INTRODUCTION 64. Conditions of § 67 35 STRESSES IN BRIDGE ...
Page 36
... zero ; ( 2 ) the algebraic sum of their horizontal components is equal to zero ; ( 3 ) the algebraic sum of their moments about any point or line is equal to zero . B A X S H If S , Fig . 27 , represents the stress in any member ; H ...
... zero ; ( 2 ) the algebraic sum of their horizontal components is equal to zero ; ( 3 ) the algebraic sum of their moments about any point or line is equal to zero . B A X S H If S , Fig . 27 , represents the stress in any member ; H ...
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Common terms and phrases
area of cross-section assumed beam bending bending moment center of gravity center of moments chord members chord stresses compression compression members connection cot H counter csc H dead panel load dead-load stress diameter distance end posts equal equation eyebars feet flange floorbeam force polygon forces acting funicular girders horizontal component influence line intersection joints left end left reaction line of action linear foot live panel load live-load shear loaded chord main diagonal Maximum live-load stress method method of moments minimum stress Moment of Inertia panel length panel points parallel plane plate portal pounds per linear pounds per square Pratt truss R₁ radius of gyration represented in Fig rivets shear in panel shown in Fig span square inch stress diagram stress in CD stringers Table tension thickness vector vertical component W₁ Warren truss width wind pressure
Popular passages
Page 35 - Since the resultant moment of several forces about any point is equal to the moment of the resultant of the forces about...
Page 14 - The force polygon must close; for, otherwise, the vector drawn from the origin of the first vector to the end of the...
Page 18 - Rt and the resultant of the wind loads, the three external forces must meet in a point if produced. This furnishes a method for determining the reactions, where the direction and line of action of one and a point in the line of action of the other are known, providing the point of intersection of the three forces comes within the limits of the drawing board.
Page 16 - V is equal to the algebraic sum of the vertical components of the stresses in ab and Ab.
Page 12 - These floors have not been in use for a sufficient length of time to establish their suitability for this purpose.
Page 2 - A' through the truss and consider the forces acting on the part of the truss to the left of the section.
Page 15 - The maximum moment in a beam supporting two equal loads will occur under either load when the two loads are on opposite sides of the center and one of the loads is at a distance from the center equal to one-fourth the distance between the loads. 3.
Page 84 - ... the sum of the horizontal components of the stresses in the web members intersecting at that point. The results for g or h or k may be easily verified by the method of moments. Let / be the span in feet, and d the depth of a flanged beam, in feet also ; then if w is the load per foot, the flange stress at the centre, as is well known, will...
Page 14 - X 6", or i" bolt 6" long, would mean a bolt having a shank \" in diameter and 6" long from the under side of the head to the end of the stem, having the dimensions of the bolt shown in Fig. 62. The dimenFig.
Page 20 - The theorem states that the moment of inertia of the mass of a body with respect to any plane is equal to the sum of the moment of inertia of the...